An electron in the ground state of a hydrogen atom absorbs a photon of wavelengt

Question

An electron in the ground state of a hydrogen atom absorbs a photon of wavelength 97.4 nm. A. What's energy of photon in ev? b.after absorbing energy, what's the final n value of electron? C. What's electrons new angular momentum in terms of h? D. After emitting a photon, electron has z component of angular momentum equal to -2h. Fill in quantum number for n, l, ml for before, after absorbing and for after emission An electron in the ground state of a hydrogen atom absorbs a photon of wavelength 97.4 nm. A. What's energy of photon in ev? b.after absorbing energy, what's the final n value of electron? C. What's electrons new angular momentum in terms of h? D. After emitting a photon, electron has z component of angular momentum equal to -2h. Fill in quantum number for n, l, ml for before, after absorbing and for after emission b.after absorbing energy, what's the final n value of electron? C. What's electrons new angular momentum in terms of h? D. After emitting a photon, electron has z component of angular momentum equal to -2h. Fill in quantum number for n, l, ml for before, after absorbing and for after emission

Explanation / Answer

(a) Energy=hc/wavelength=2.04*10^(-18) J or 12.75 eV

(b) We know energy is quantised for electron

we know

1/wavelength=R(1/n1^2 -1.n2^2)

putting we got n2=3.94

so if we take rough estimate it will be n=4

(c) new angular momentum=nh/2pi=4*h/2pi=4.21*10^(-34)

(d) angular momentum is always (ml)h/2pi so

ml=-2

if m=-2

l can be 2,3,4,5,....

n =3,4,5,,,,,

since n=4 after absorbing ,l=3 ,ml=-2

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