A circular coil enclosing an area of 96 cm2 is made of 198 turns of copper wire.

Question

A circular coil enclosing an area of 96 cm2 is made of 198 turns of copper wire. The wire making up the coil has resistance of 6.0 , and the ends of the wire are connected to form a closed circuit. Initially, a 1.2 T uniform magnetic field points perpendicularly upward through the plane of the coil. The direction of the field then reverses so that the final magnetic field has a magnitude of 1.2 T and points downward through the coil. If the time required for the field to reverse directions is 0.19 s, what average current flows through the coil during that time?

Explanation / Answer

using Faraday's Law:

E = N d (BA) / dt

E = ( 198 ) ( 1.2 T ) ( 0.0096 m^2 ) / .19 s

E = 12 V so I = E / R = 12 V / 6 Ohms = 2 A

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