A circular coil 14.0 cm in diameter and containing nine loops lies flat on the g

Question

A circular coil 14.0 cm in diameter and containing nine loops lies flat on the ground. The Earth's magnetic field at this location has magnitude 4.50×105T and points into the Earth at an angle of 58.0 below a line pointing due north. A7.80-A clockwise current passes through the coil.

Part A

Determine the torque on the coil.

Express your answer using three significant figures and include the appropriate units.

Part B

Which edge of the coil rises up: north, east, south, or west?

Which edge of the coil rises up: north, east, south, or west?

Explanation / Answer

(a) The angle between the normal to the coil and the field is (90 - 58 )degree , so the torque is

                    t = NIABsinq

                    t = (9 ) (7.80A) * pie *(0.07m)^2 * (4.50 * 10^-5T)sin(90 - 58)

                    t =   2.57 * 10^-5m.N.

the torque on the coil is 2.57 * 10^-5 m N

         (b) From the directions of the forces shown on the diagram,

                 the    north edge   of the coil will rise.

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