Problem 29.60 Two 15-cm-diameter electrodes 0.54 cm apart form a parallel plate

Question

Problem 29.60 Two 15-cm-diameter electrodes 0.54 cm apart form a parallel plate capacitor. The electrodes are attached by metal wires to the terminals of a 12 V battery. What are the charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes Part A What are the charge on each electrode, the electric field strength inside the capacitor, and the potential difference between the electrodes while the capacitor is attached to the battery? Express your answer using two significant figures. Submit My Answers Give Up Part B Express your answer using two significant figures. V/ms My Answers Give Up Part C Express your answer using two significant figures. AV My Answers Give Up

Explanation / Answer

A)Capacitance is given by:

C = epsilon0 A/d

C = 8.85 x 10^-12 x 3.14 x 0.075^2/0.0054 = 2.89 x 10^-11 F

Q = CV

Q = 2.89 x 10^-11 x 12 = 34.68 x 10^-11 C

Hence, Q = 34.68 x 10^-11 C

B)Electric field will be:

E = V/d

E = 12/0.0054 = 2.22 x 10^3 V/m

Hence, E = 2.22 x 10^3 V/m

C)V = Ed

V = 2.22 x 10^3 x 0.0054 = 12 V

Hence, V = 12 V

D)As the gap increased, the C become

C = epsilon0 A/d'

C = 8.85 x 10^-12 x 3.14 x 0.075^2/0.012 = 1.303 x 10^-11 F

Q = CV

Q = 1.303 x 10^-11 x 12 = 15.64 x 10^-11 C

Hence, Q = 15.64 x 10^-11 C

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