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Problem 27.61 A compound microscope has the objective and eyepiece mounted in a

ID: 1268167 • Letter: P

Question

Problem 27.61

A compound microscope has the objective and eyepiece mounted in a tube that is 17.0cm long. The focal length of the eyepiece is 2.52cm , and the near-point distance of the person using the microscope is 25.0 cm.

Part A

If the person can view the image produced by the microscope with a completely relaxed eye, and the magnification is -4525, what is the focal length of the objective?

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Problem 27.61

A compound microscope has the objective and eyepiece mounted in a tube that is 17.0cm long. The focal length of the eyepiece is 2.52cm , and the near-point distance of the person using the microscope is 25.0 cm.

Part A

If the person can view the image produced by the microscope with a completely relaxed eye, and the magnification is -4525, what is the focal length of the objective?

fobj = mm

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Explanation / Answer

Given data

Image distance is di = 2.52 cm -(17.0 cm)

                                    =- 14.48 cm

Focal length of eyepiece is fe= 2.52 cm

Near point distance N= 0.250 m

Total Magnification is M=-4525

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The expression for total magnification is,

              Mtotal= -(di)(N)/((fO)(fe))

The Focal length of the objective eyepiece is,

       fO= -(- 14.48 cm)( 0.250 m)/(( -4525)( 2.52 cm))

= 3.175x10^-4 m

           =0.318x10^-3 m

           =0.318 mm

Therefore, the objective focal length is 0.318 mm.

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