Problem 26.17 A thin film of polystyrene of refractive index 1.49 is used as a n

Question

Problem 26.17 A thin film of polystyrene of refractive index 1.49 is used as a nonreflecting coating for Fabulite (strontium titanate) of refractive index 2.409.
Part A What is the minimum thickness of the film required? Assume that the wavelength of the light in air is 450nm Problem 26.17 A thin film of polystyrene of refractive index 1.49 is used as a nonreflecting coating for Fabulite (strontium titanate) of refractive index 2.409.
Part A What is the minimum thickness of the film required? Assume that the wavelength of the light in air is 450nm A thin film of polystyrene of refractive index 1.49 is used as a nonreflecting coating for Fabulite (strontium titanate) of refractive index 2.409.
Part A What is the minimum thickness of the film required? Assume that the wavelength of the light in air is 450nm Part A What is the minimum thickness of the film required? Assume that the wavelength of the light in air is 450nm

Explanation / Answer

There will be a phase shift as each reflection so they cancel out and the only path difference will come from the thickness of the film. And the wavelength will shorten in the film so

λ/2 = µ . 2 . t

t = λ / 4 µ = 450 nm / 4 . 1.49 = 75.5 nm

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