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Problem 25.71 -MC 9 of 10 > tant Part A Unpolarized light of intensity 1.4 W/m2

ID: 2040046 • Letter: P

Question

Problem 25.71 -MC 9 of 10 > tant Part A Unpolarized light of intensity 1.4 W/m2 passes through a vertical polarizing filter. The light then passes through a second polarizer whose axis 51° from the vertical. The light then passes through a third polarizer whose axis is horizontal What is the intensity of the transmitted light after passing through the horizontal polarizer? Assume that the polarizers are close enough to each other that the light's intensity changes only when passing through a polarizer and not as it travels between them. (Figure 1) Express your answer using three significant figures, and please include the proper unit. Figure 1 of 1 View Available Hint(s) Unpolarized light HA Value Units Submit Provide Feedback Next >

Explanation / Answer

Here , for the light after passing through the first polarizer

the intensity will be 1/2

final intensity = 0.50 * Io * cos^(51) * cos^2(90 - 51)

final intensity = 0.50 * 1.4 * cos^(51) * cos^2(90 - 51)

final intensity = 0.17 W/m^2

the final intensity is 0.17 W/m^2

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