Problem 25 Part C???? Reaction Rates Consider the reaction: 2 HBr(g) rightarrow

Question

Problem 25 Part C????

Reaction Rates Consider the reaction: 2 HBr(g) rightarrow H2(g) + Br2(g) Express the rate of the reaction with respect to each of the reactants and products. In the first 25.0 s of this reaction, the concentration of HBr dropped from 0.600 M to 0.512 M. Calculate the average rate of the reaction in this time interval. If the volume of the reaction vessel in part b was 1.50 L, what amount of Br2 (in moles) was formed during the first 15.0 s of the reaction? 2N20(g) rightarrow 2 N2(g) + 02(g) Express the rate of the reaction with respect to each of the reactants and products. In the first 15.0 s of the reaction, 0.015 mol of 02 is produced in a reaction vessel with a volume of 0.500 L. What is the average rate of the reaction over this time interval? Predict the rate of change in the concentration of N20 over this time interval. In other words, what is Delta[N20]/Delta t ? For the reaction 2 A(g) + B(g) rightarrow 3 C(g), Determine the expression for the rate of the reaction with re

Explanation / Answer

rate of reaction = (0.600 M - 0.512 M) / 25 = 0.00352 M/s = 0.00352 mole/ L.s

Thus mole of HBr reacted after 15 sec = 0.00352*15 = 0.0528 mole

mole of Br2 formed = mole of HBr reacted /2 = 0.0528/2 = 0.0264 mole/L

for 1.5 L mole of Br2 formed = 0.0264*1.5 = 0.0396 mole

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