A diverging lens has a focal length of magnitude 20.4 cm. (a) Locate the images

Question

A diverging lens has a focal length of magnitude 20.4 cm. (a) Locate the images for each of the following object distances. 40.8 cm distance location 20.4 cm distance location 10.2 cm distance location (b) Is the image for the object at distance 40.8 real or virtual? real virtual Is the image for the object at distance 20.4 real or virtual? real virtual Is the image for the object at distance 10.2 real or virtual? real virtual (c) Is the image for the object at distance 40.8 upright or inverted? upright inverted Is the image for the object at distance 20.4 upright or inverted? upright inverted Is the image for the object at distance 10.2 upright or inverted? upright inverted (d) Find the magnification for the object at distance 40.8 cm. Find the magnification for the object at distance 20.4 cm. Find the magnification for the object at distance 10.2 cm.

Explanation / Answer

1/di + 1/do = 1/f

for diverging lens f = negative

f = -20.4 cm

a )

i)do = 40.8 cm

1/di = 1/f - 1/do

di = -13.6 cm

ii)

do = 20.4 cm

di = -10.2

iii)

do = 10.2 cm

di = -6.8 cm

part b )

all images are virtual

part c )

all are upright

part d )

m = -di/do

i )

m = -(-13.6)/40.8 = 0.33

ii )

m = -(-10.2)/20.4 = 0.5

iii)

m = -(-6.8)/10.2 = 0.667

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