3a. In a population of guppies, a dark mutant form arises thatleads to superior

Question

3a. In a population of guppies, a dark mutant form arises thatleads to superior camouflage. Suppose that in a population of 500guppies, there is a single mutant Dd individual, with D (dark)dominant over d(light). Dark guppies enjoy a 10% greaterprobability of survival to reproductive age. Assuming that oncethey reach this age each individual produces the same averagenumber of offspring, what is the expected frequency of dark guppiesin the next generation? what is the frequency of the dark allele D?Ignore the effects of random sampling. 3b.what is the expected frequency of D in the next generationif D is recessive (i.e. Dd individual are light)? please i would like to learn how to do tis since it will be onmy exam. 3a. In a population of guppies, a dark mutant form arises thatleads to superior camouflage. Suppose that in a population of 500guppies, there is a single mutant Dd individual, with D (dark)dominant over d(light). Dark guppies enjoy a 10% greaterprobability of survival to reproductive age. Assuming that oncethey reach this age each individual produces the same averagenumber of offspring, what is the expected frequency of dark guppiesin the next generation? what is the frequency of the dark allele D?Ignore the effects of random sampling. 3b.what is the expected frequency of D in the next generationif D is recessive (i.e. Dd individual are light)? please i would like to learn how to do tis since it will be onmy exam.

Explanation / Answer

   1) This is is how i would figure on how tosolve this... 1out of 500 posses the Dark allele and the rest arelight now lets say the 500 once the reach there mating season andthen give birth they each give out 4 children. what i am unsureabout is the combination of the father and mother allele's or whatwould they be. So i can only assume that the 500 mate with a ddopposite. in which we would combine the dark one (Dd) with alight one (dd). In which his/her offspring would look likethis>>> Dd, Dd, dd, dd. Half of them would be Dark. Nowthe other 499 light fish would mate with another light fish andthere children would be dd,dd, dd, dd. All light. To get the totalnumber of offspring born times 4X500 (the number of children foreach parent to the number of parents) which would be 2000. you knowthat out of 2000 there are to fish that are dark so 2 out of 2000posses the dark allele. 2/2000 or 1/1000. so out of every 1000 fishthere will be one that possess the dark trait.

   2) for this you would figure it the same wayas the top this time since the Dd is recessive then all thechildren would be light but only 1/1000 would possess the hiddengene.

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