2) A 0.060 kg golf ball is at rest and has a velocity of 100. m/s immediately af

Question

2) A 0.060 kg golf ball is at rest and has a velocity of 100. m/s immediately after being hit. If the golf club and ball were in contact for 0.800 ms, what is the average force exerted on the ball? ( ,060) (100) , 1O0x103 3) A 1.30 kg mass moving at 17.6 m/s collides with a stationary mass of 1.25 kg. If the two masses stick together, what is their combined velocity immediately after the collision? 4) A 1250 kg howitzer fires a 11.1 kg mass at 40.0 m/s in the horizontal direction. What is the recoil velocity of the howitzer? Assume that frictional forces are negligible.

Explanation / Answer

2)We know from the defination of impulse

J = force x time

Also; J = m (v2 - v1)

equating the two:

F t = m (v2 - v1)

F = m (v2 - v1)/t

F = 0.06 (1 - 0)/0.8 x 10^-3 = 75 N

Hence, F = 75 N

3)We know from conservation of momentum

Pi = Pf

m1v2 + m2v2 = (m1 + m2)vf

vf = (m1v1 + m1v2)/(m1 + m2)

vf = (1.3 x 17.6 + 1.25 x 0)/(1.3 + 1.25) = 8.97 m/s

Hence, vf = 8.97 m/s (= 9 m/s)

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