2) A 0.2m long cylinder has a movable piston with radius 0.02m a) What is the vo

Question

2) A 0.2m long cylinder has a movable piston with radius 0.02m a) What is the volume of the cylinder? Given that V- (Area of the circular base ) x (Length of cylinder) b) c) d) If the piston is pushed 0.05m what is the new volume V' of the cylinder? Given that V'- (Area of the circular base) x (New length) if initial pressure was atmospheric at P=101 kPa at T:0 co, what is the air pressure P' inside the cylinder when the piston is pushed down 0.05m? Given that P's VP/v If the temperature inside the cylinder reached 30co from initial of 0°; what is the new pressure? Given that we use Boyles and Charles law combined; P's VPT/V'T and T in Kelvin Tin c+273

Explanation / Answer

a] Volume V = pi r^2 * L

= pi*0.02^2*0.2 = 0.000251 m^3

b] V' =  pi r^2 * L' = pi*0.02^2*(0.2-0.05) = 0.0001885 m^3

c] P' = VP/V' = 0.000251*101/0.0001885 = 134.5 kPa

d] P' = VPT'/V'T = 0.000251*101*(30+273)/[0.0001885*(0+273)] = 149.3 kPa

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