59 A top fuel dragster accelerates from a rest with an acceleration of 5.10 g\'s

Question

59 A top fuel dragster accelerates from a rest with an acceleration of 5.10 g's. Once the dragster reaches its top velocity of 145 mV, it travels at aconstant velocity for the rest of the 114 miles track. How much time did it take for the dragster to travel the length of the rack? 68 A bus picks up a passenger and accelerales fron a rest at 1.50 m's2 for 6.00 seconds. After the initial 6.0 seconds the bus accelerates at 2.50 nh2 for an additional 35.5 m·The bus then slams on the brake and accelerates at-0.75 g's until it comes to a rest. a What is the total time for the bus ride? b What is the total distance covered by the bus?

Explanation / Answer

59)acceleration = 5.1*9.8=49.98 m/s2

top velocity = 145 m/s

time taken to reach top speed= 145/49.98=2.9 seconds

time taken for 0.25 miles(402.336 m) = 402.336/145=2.77 seconds

total time taken = 2.9+2.77=5.67 seconds

60)a)initial acceleration for 6 seconds= 1.5 m/s2

velocity after 6 seconds = 1.5*6=9 m/s

distance travelled = 0.5*1.5*62=27 m

for the next 35.5 m, the bus accelerates at 2.5 m/s2

velocity after travelling 35.5 m = sqrt(92+2*2.5*35.5)=16.1 m/s

time taken to reach 16.1 m/s from 9 m/s = (16.1-9)/2.5=2.83 seconds

After this, the bus decelerates with deceleration 0.75*9.8=7.35 m/s2

time taken to come to rest = 16.1/7.35=2.19 seconds

Total time for which the bus travels = 6+2.83+2.19=11.02 seconds

b)distance travelled while coming to rest = 16.12/(2*7.35)=17.63 m

Total distance travelled = 27+35.5+17.63=80.13 m

Related Questions

Navigate

• Browse (All)
• Browse 5
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.