58% D Tue 12:00 PM a E Chrome File Edit View History Bookmarks People Window Hel

Question

58% D Tue 12:00 PM a E Chrome File Edit View History Bookmarks People Window Help Mastering Chemistry: Chapte https:// session masteringchemistry.com/ myct/itemView? assignment ProblemID-49021123&offset; next Robbie Bb dyn General Chemistry II Summer 2015 He Close www.che t Gibbs Free Energy and Equilibrium Chapter 17 Chegg previous 9 of 9 l return to assignmen t Gibbs Free Energy and Equilibrium To determine whether a chemical reaction is spontaneous you need to calculate the Gibbs free energy AG for the reaction. A negative free-energy value indicates that the reaction is spontaneous as written. The magnitude of the equilibrium constant can be used to determine The reaction relative amounts of reactants and products at equilibrium. An equilibrium constant that is large in SO2 (g) 2H2S(g) 3S(s) 2H20(g) magnitude (Kp X 1) indicates significantly more products than reactants. In principle, this is the basis of a suggested method for removal of reaction is a feasible method to remove SO2; however, H2S is a highly toxic gas that reduces the SO2, a pollutant that irritates airways causing oxygen-carrying capacity of the blood. Its use would pose a safety hazard for plant workers and coughing, from power-plant stack gases people in the nearby area The values below may be helpful when answering kn questions about the process but Part C AG AH Substance (kJ/mol) (kJ/mol) Assume that the partial pressure of sulfur dioxide, PK s equal to the partial pressure of dihydrogen SO H2O(g -28.6 -241.8 sulfide, PHss, and therefore P PELs the vapor pressure of water is 25 torr calculate the SO equilibrium partial pressure of SO2 n the system at 298 K SO H2O (l) -237.1 -285.8 Express the pressure in atmospheres to two significant figures. SO2 (g -300.4 -296.9 TED spol 99% H2S(g) -3301 -20.17 Pso atm Subm an Hints My Answers Give Up Review Part Part D Using relative enthalpy and entropy values, determine h the process is affected a each of the following temperature or pressure changes. Consider that a more effective reaction produces m product or more product in a shorter amount of time. Drag the appropriate items to their respective bins 500

Explanation / Answer

equilibrium expression

Kp= Rho(H20)^2/ (Rho(SO2)*Rho(H2S)^2)

Remember that the solid sulfur doesn't participate in the gas equation.

Convert

Torr to ATM

25 Torr/ 760 = .032895 ATM

You're told the two Rhos on the bottom are the same. You calculated Kp in the previous part. Plug them in:

8.18*10^15 = (.032895^2)/x^3

Solve for x

x= (.032895^2 / 8.18*10^15) ^ (1/3)

x= 5.1 * 10^-7

Related Questions

Navigate

• Browse (All)
• Browse 5
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.