Answer D-F Constants Part A Some cell walls in the human body have a layer of ne

Question

Answer D-F

Constants Part A Some cell walls in the human body have a layer of negative charge on the inside surface and a layer of positive charge of equal magnitude or the outside surfacs. Suppose that the charge density on either surface is 0.50 x 10 Find the magnitude of E in the wall betiwoon the two layers of charge. Express your answer using two significant figures. C/m the cell wall s 4.6 nm thick, and the cell-wall material is air Correct Part B Find the potential difference between the inside and the outside of the cell. Express your answer using two significant figures. dW=0.26 V Correct Part C Which wal of the cell is at the higher potential? the inner wall the outer wall

Explanation / Answer

Part D:

The electric field energy per unit area Ed is given by 0.50V^2/d where 0= 8.85*10^-12, V= 0.26V as calculated before, d= 4.6*10^-9m,

So, Ed= 0.5*8.85*10^-12* 0.26^2/ 4.6*10^-9 = 6.5*10^-5 J/m^2

Now, volume of cell is 10^-16 m^3. Or, 4r^3 / 3 = 10^-16.

So, r= 2.88*10^-6m

So, the total area of cell is A= 4r^2= 1.04*10^-10 m^2

So, total electric field energy stored in the wall of the cell is E= Ed*A = 6.5*10^-5 * 1.04*10^-10 = 6.8e-15 J

Part E:

Here, dielectric constant is 5.5. So, the magnitude of E in the wall between the two layers of charge is

Ed= ((Q/A)/5.5*0)

So, Ed= 5.7*10^7 / 5.5 = 1.0e7 V/m

Part F:

Now, the potential difference between the inside and the outside of the cell is V = Ed*d = 1.036*10^7* 4.6*10^-9

So, V = 0.048V

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