1. A gas is found to exert 6.85 atm at 45 celsius. What pressure would change th

Question

1. A gas is found to exert 6.85 atm at 45 celsius. What pressure would change the temperature to 100 celsius?
a. 3.1 atm
b. 5.8 atm
c. 8.0 atm
d. 15.2 atm
please explain step by step

2. what is the mass of a substance that transfers 1255cal with a specific heat capacity of 0.36kj x celsius, an inital temperature of 52 fahrenheit and final temperature of 68 fahrenheit ?
a. 1.6 kg
b. 392 kg
c. 1639 kg
d. 391700kg
please explain step by step

3. What is the specific heat capacity of a 23000 mg object that transfers 56J of energy, while its temperature jumps from 582K to 621K?
a. 0.06kj / kg x celsius
b. 0.6 kj / kg x celsius
c. 7.3 kj / kg x celsius
d. 9.7 kj / kg x celsius
please explain step by step

4. A truck driver traveled a distance of 35 kilometers in 6hrs. What is the rate of which he covered this distance?
a. 0.16 m/s
b. 1.6 m/s
c. 5.8 m/s
d. 9.7 m/s
please explain step by step

5. Which has a greater change in kinetix energy, a 1000kg car traveling from 5 m/s to 19 m/s or a 1680kg truck traveling 5 m/s to 15 m/s?
a. the car
b. the truck
c. both have the same change in kinetic energy

please explain step by step

Explanation / Answer

1.

Ideal gas equation is,

PV = nRT, if the volume is constant and if initial pressure and temperature are P1 and T1 and final pressure and temepratre P2 and T2 respectively then,

P1/T1 = P2/T2

p, P2 = P1T2/T1 = (6.85 atm)(100 + 273)K/(45 + 273)K

or, P2 = 8 atm,

So correct option is c.

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2.

mention spcific heat correctly.

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3.

Q = ms(T2 - T1)

or, 56 J = (0.023kg)s(621K - 582 K)

or, s = 62.43 J/kg-K = 0.06kJ/kg-K

So, the correct option is a.

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4.

Speed = 35 km/6h = 35000m/(6X3600s) = 9.72m/s

So the correct option is d.

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5.

chang in KE for 1000 kg car = (1/2)(1000 kg)((19 m/s)2 - (5m/s)2) = 168,000 J

chang in KE for 1680 kg car = (1/2)(1680 kg)((15 m/s)2 - (5m/s)2) = 168,000 J

So both have same change in kinetic energy.

So the correct option is c.

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This concludes the answers. Check the answer and let me know if it's correct. If you need any more clarification or correction, feel free to ask.....

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