1. A force F acts on a rectangular block to slide the block with constant speed,

Question

1. A force F acts on a rectangular block to slide the block with constant speed, as seen in the ?gure below.

Find the coe?cient of friction.

2. How far from the lower left corner does the normal force act?

Answer in units of cm

Explanation / Answer

1). from equilibrium of forces in vertical direction; 410 = N + 234 sin 30 => N = 293 N from equilibrium of forces in horizontal direction; u*N = F *cos 30 => u*293 = 234*cos 30 => coefficient of friction, u = 0.692 2). for torque equilibrium about the lower left corner; F* cos 30* 44 + 410 *41 = N *x + F *sin 30* 82 => 293x + 9594 = 8916.6 + 16810 => x= 55.06 cm

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.