1. A football is thrown with an inital velocity of 46mph at an angle of 33 degre

Question

1. A football is thrown with an inital velocity of 46mph at an angle of 33 degrees. How many yards down the field does the ball land? Distance= _____ yards

2. An arrow is show with a velocity of 34 m/s at an angle of 50 degrees. What is the maximum height attained? What is the horizontal projection? Height= ______ meters Range= _____ meters

3. A putting green isolated 190 feet horizontally and 35 feet vertically from the tee. What must be the magnitude and direction of the final velocity if a ball is to strike the green at this location after a time of 2.5 seconds? Inivial velocity magnitude= _____feet/sec Inital velocity angle= ______ degrees

4. A 56 Newton block rests on a 35 degree incline plane. Determine the normal force perpendicular to the plan and the frictionforce parallel to the plan that keeps the block from sliding. Normal force= ______ newtons Friction force= ____ newtons

**Please show with proper paranthesees, I think I am just putting the equations into my calculator wrong and that is why I am not coming to the correct answers. Thank you!

Explanation / Answer

You can write multiple questions in a single question, better to write all questions seperately.

Any how I am providing you the solution of question 1

(1) Let's use metric units, which is easier. 86 mph = 20.5638 m/s. The upward component of that velocity is sin(33) * 20.5638 = 11.2 m/s.

First question: how long before the ball lands? Since the accelation due to gravity is 9.8 m/sec^2, we compute 11.2 / 9.8 = 1.143 seconds until the ball's vertical velocity is zero (at the top of its arc), and another 1.143 seconds until it comes down, for a total of 2.286 seconds.

Second question: how far will the ball travel HORIZONTALLY in 2.286 seconds? To make it easy, we will ignore air resistance. The horizontal component of the ball's velocity is cos(33) * 20.5638, which is 17.246 m/s . So the distance travelled will be 17.246 * 2.286, or 39.425 meters. That's 43.11570429 yards

(2) In this question same way find vertical component of the speed , then divide it by gravity to find time, then multiplies that time to the vertical velocity to get the maximum height attained.

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