A 60.0 g ball of clay is thrown horizontally with a speed of 12.0 m/s toward a 8

Question

A 60.0 g ball of clay is thrown horizontally with a speed of 12.0 m/s toward a 890 g block resting on a frictionless surface. It hits the block and sticks. The clay exerts a constant force on the block during the 12.0 ms it takes the clay to come to rest relative to the block. After 12.0 ms , the block and the clay are sliding along the surface as a single system.

Part A

What is their speed after the collision?

Express your answer with the appropriate units.

Part B

What is the force of the clay on the block during the collision?

Express your answer with the appropriate units.

Part C

What is the force of the block on the clay?

Express your answer with the appropriate units.

Explanation / Answer

A) Apply energy conservation we get

1/2*60(12)2 =1/2(890+60)v2

v = 3.0157

B) Force = change in momentum * time ={ (950)*3.0157 -60*12 }*12*10-3 = 25.738N

c)both bodies apply equal and oppossite force = 25.738N

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