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ID: 1550603 • Letter: 0
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00 Sun Mar 302 z Detats Booking l zocdc x Terms of use zocdec x Google Maps x wi 4.2 Homework Mean val x wieyPtus ps://edugen wiley plus.com ledugen/student/mainfr.uni G Google D Assignment oeyA a Amazon.com Yo... PRNSL Email 0 UM Email a YouTube & vacanon Rentals,... M Twitter n Facebook-Log in... e Grammarty Halliday, Fundamentals of Physics, 10e PHYSICS FOR SCIENCE AND ENGINEERING (PHYs 2110/2120) Assignment Gradebook. Chapter 10, Problem 061 kg with 920 m. rotating at revmin. must stopin 30.05. (a) How much work must be done to sop it? (b) wratis the required average power? Give absolute values for both parts. be brouart to a (a) Number (b) Number cick if you would uke to show work for this questiont geensbom By accessing this question Assistance, you wa earm whae you earn points based on the Point Potenbal Poncy set by Your instructor. Question Attempts 0 of used teen Maomum available ormryou ansMermis question correctly attempts lessExplanation / Answer
m = 15.0 kg
r = 0.920 m
w = 331 rev/min = 34.66 rad/s
t = 30.0 s
Moment of Inertia, I = m*r^2 = 15 * 0.92^2 = 12.7 kg m^2
Work done = Change in Rotational kinetic Energy
W = 1/2 * I * w^2
W = 1/2 * 12.7 * 34.66^2 J
W = 7628 J
(b)
Pavg = W/t
Pavg = 7628 / 30
Pavg = 254 W
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