0/17/2017 10:55 PM 24.8/100 10/17/2017 12:20 PM -d Penodic Table Print Calculato

Question

0/17/2017 10:55 PM 24.8/100 10/17/2017 12:20 PM -d Penodic Table Print Calculator Gr tion 25 of 27 neral Chemistry 4th Edition University Science Books presented by Sapling Leaming Ma An equilibrium mixture of PCl(g). PCblg), and Cllg) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respectively. A quantity of Claig) is injected into the mixture, and the total pressure jumps to 263.0 Torr (at the moment of mixing). The system then re-equilibrates. The appropriate chemical equation is Calculate the new partial pressures after equilibrium is reestablished Number PCI, Torr Number Torr Ci, Number Torr PCI, Hint oPrevious Give Up & View Soldon O Check Answer Next Exit 17

Explanation / Answer

First, let us define the equilibrium constant for any species:

The equilibrium constant will relate product and reactants distribution. It is similar to a ratio

The equilibrium is given by

rReactants -> pProducts

Keq = [products]^p / [reactants]^r

For a specific case:

aA + bB = cC + dD

Keq = [C]^c * [D]^d / ([A]^a * [B]^b)

Kp = PPCl5 / (PPCl3)(PCl2)

Kp = (217)/(13.2*13.2) = 1.2454

after we add CL2(reactatnts)

Ptotal = 217 + 13.2 + 13.2 = 243.4

Pafter addition = 263 - 243.4 = 19.6 torr was added of CL2

intially:

PCl3 =13.2

Cl2 =13.2+19.6 = 32.8

PCl5 = 217

after equilibirum

PCl3 =13.2 - x

Cl2 = 32.8 - x

PCl5 = 217 +x

substitute in Kp

Kp = PPCl5 / (PPCl3)(PCl2)

1.2454 = (217 +x) / (13.2 - x)(32.8 - x)

13.2 *32.8 - (13.2+32.8)x + x^2 = 217/1.2454 + x/1.2454

432.96 - 46x + x^2 = 174.24 + 0.8029x

x^2 + (-46-0.8029)x + (432.96 -174.24 ) = 0

x^2 -46.8029x + 258.72 = 0

x = 6.404

PCl3 =13.2 - 6.404 = 6.796 torr

Cl2 = 32.8 - 6.404 = 26.396 torr

PCl5 = 217 +6.404 = 223.404 torr

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