0/2 points 1 Previous Answers Giancoli7 3.P.O68. My Notes Ask Your T Me I think

Question

0/2 points 1 Previous Answers Giancoli7 3.P.O68. My Notes Ask Your T Me I think this question is set up incorrectly Fridey, Sep 15,347P Drenscko, Mihaela No, it is not. Hint: eliminate time from horizontal position equation and insert it in vertical position equation, then sclve for vo twice, first setting x to 11-0.22, then to 11-0.22 Friday, Sep 15,8.03PM Ask Your Teacher Send t a height of 2.10 m above the floor. The basket is 2.60 m above the floor. The If the shot is made from a horizontal distance of 12.so m and must be accurate to ± 0.22 m (horizontally), what is the basket? Enter your answer to at least four significant digits. range of initial speeds allowed to make the lowest initial speed 10.70 m/s highest initial speed 10.76 x m/s Submit Answer Save ProgressPractice Another Version My Notes Ask Your + 1/1 points 1 Previous Answers W2 template (1).8md 9 8 7 6

Explanation / Answer

y = h+xtan(theta) - gx^2/(2v^2*cos^2(theta))

y = 2.60 m
h = 2.10 m
theta = 37 degree
x = 12.5 +- 0.22

First calculate for x = 12.5-0.22 = 12.28m
2.6=2.1+12.28tan37 - (9.8(12.28)^2)/((2v^2cos^2(37))
=> v = 11.5 m/s

Now calculate for x = 12.5+0.22 = 12.72m
2.6=2.1+12.72tan37 - (9.8(12.72)^2)/((2v^2cos^2(37))
=> v = 11.7 m/s

Related Questions

Navigate

• Browse (All)
• Browse
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.