0.9 liters of an ideal gas is initially at atmospheric pressure. - Process a-b:

ID: 1385736 • Letter: 0

Question

0.9 liters of an ideal gas is initially at atmospheric pressure.

- Process a-b: The gas is allowed to expand isothermally to 2.2 liters.

- Process b-c: The gas is returned to atmospheric pressure at constant volume.

- Process c-d: The gas is returned to the initial volume, 0.9 liters, at constant pressure.

A. Process a-b: Determine the amount of work that was done.
(include units with answer)

B. Process a-b: Determine the change in internal energy.
(include units with answer)

C. Process a-b: Determine the heat that was added.
(include units with answer)

D. Process b-c: Determine the work that was done.
(include units with answer)

E. Process c-d: Determine the work that was done.
(include units with answer)

from ideal gas equation P*V = n*R*T

Temparature T = (P*V)/(n*R) = (1.013*10^5*0.9*10^-3)/(1*8.314) = 10.96 K

Work done in isothermal process

W = R*T*ln(V2/V1) = 8.314*10.96*ln(2.2/0.9)= 81.45 J

B) in isothermal process temparature is constant

hence internal enrgy is also a constant

so change in internal enrgy = 0 J

C) Heta added = work done = 81.45 J

D) W = p*dV

dV is the change in volume = 0 lit

W = p*0 = 0 J

E) W = p*dV = (1.013*10^5)*(2.2-0.9)*10^-3 = 131.7 J

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