0.529g if acetylene (C2,H2;26.22g/mol) is burned in the excess O2 gas in s bomb

Question

0.529g if acetylene (C2,H2;26.22g/mol) is burned in the excess O2 gas in s bomb calorimeter (4.90kJ/degree C) increased in temp. By 5.35degree C Determine the change in energy
2C2H2(g)+5O2(g)--->4CO2(g)+2H2O(g) Delta E=? 0.529g if acetylene (C2,H2;26.22g/mol) is burned in the excess O2 gas in s bomb calorimeter (4.90kJ/degree C) increased in temp. By 5.35degree C Determine the change in energy
2C2H2(g)+5O2(g)--->4CO2(g)+2H2O(g) Delta E=? Determine the change in energy
2C2H2(g)+5O2(g)--->4CO2(g)+2H2O(g) Delta E=?

Explanation / Answer

bomb calorimeter Cp = 4.90 kJ/oC

temperature difference dT = 5.35 oC

heat energy = Cp x dT

= 4.90 x 5.35

= 26.215 kJ

moles of acetylene = 0.529 / 26.22 = 0.020

change in energy

Delta E = 26.215 / 0.02

= -1310.75 kJ

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