0.47 got 1,1.1 -trichlorocthane is introduced into a glass bottle containing 1.8

Question

0.47 got 1,1.1 -trichlorocthane is introduced into a glass bottle containing 1.83 L of pure water and 4.68 g of activated carbon such that the bottle is filled to the brim (i.e., no air in the bottle). Afterwards, the bottle is scaled and left to equilibrate. The sorption of 1,1,1-trichlorocthane on activated carbon can be described by a Freundlich Isotherm. Does 1,1,1 -trichlorocthane form a separate liquid phase in the glass bottle? Explain your answer. Calculate the concentration of 1,1,1-trichlorocthane dissolved in water (in mg/L) and the amount that is sorbed on activated carbon (in mg/g) at equilibrium. When equilibration is reached, all the activated carbon with the sorbed 1,1,1-trichloroethane is filtered and removed from the bottle and introduced into a second bottle which is filled to the brim with 2.55 L of pure water (i.e., no air in the second bottle). The second bottle is sealed and left to equilibrate. What is the concentration of dissolved 1,1,1-trichloroethane in the water in the second bottle at equilibrium? Express your answer in mg/L

Explanation / Answer

c)Since 1,1,1,-trichloroethane is poorly soluble in water it will form a separate liquid in the glass bottle.

d) Concentration of 1,1,1,- trichloroethane dissolved in water (mg/L)

solubility of 1,1,1-trichloroethane is 0.4 % in water

i.e 0.3-0.5g dissolves in1 L water

? in               g in dissolves in 1.83 L water

=> (1.83*0.5)/1=0.915 grams will dissolve in 1.83 L water

moles of 1,1,1-trihcloroetahne =0.915/131.4g/mole= 0.007 moles

Molarity of 1,1,1-trichlooethane= 0.007/1.83=0.004 M

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