0.2500 g of zinc reacts with 50.00 mL of 0.1000 M hydrochloric acid to yield hyd

Question

0.2500 g of zinc reacts with 50.00 mL of 0.1000 M hydrochloric acid to yield hydrogen gas. (a) Identify the limiting reagent and calculate the theoretical yield of hydrogen gas in mols. (b) If the hydrogen produced in (a) is collected over water, calculate the total volume of hydrogen gas which would be collected at 760 mm Hg and 25 degrees celsius. (Hint: Will a second gas be present in the sample collected by water displacement?) SHOW ALL WORK PLEASE!

Explanation / Answer

Zn + 2HCl --> ZnCl2 + H2 mol of Zn = 0.2500/65.39 = 0.00382 mol mol of HCl = 10.00 x 0.1/1000 = 0.001 mol From the equation you need 2 mol of HCl for every 1 mol of Zn and this would make 1 mol of H2 You do not have enough acid to react with all the Zn so HCl is limiting. We know for every 2 mol of HCl you would make 1 mol of H2 So for 0.001 mol of HCl you would make 0.0005 mol of H2

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