0/2 points 16 18.4.WA.036 A proton is initially at rest. After some time, a unif
ID: 1573672 • Letter: 0
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0/2 points 16 18.4.WA.036 A proton is initially at rest. After some time, a uniform electric field is turned on and the proton accelerates. The magnitude of the electric field is 1.33 × 10s NC (a) What is the speed of the proton after it has traveled 2.00 cm What kinematic equations are relevant here? How does Newton's Second Law relate to the electric force? m/s (b) What is the speed of the proton after it has traveled 20.0 cm? What kinematic equations are relevant here? How does Newton's Second Law relate to the electric force? m/s Reading 18.5 WA 038 surface and are placed in the diagram as shown. The charges of each marble are q1-57S C, q2-1.65 ic, and Three charged marbles are glued to a qs--2.30 pC, Marble q, is a -3.00 cm to the left of the marble a,, while marble a, is a distance r 2.00 cm to the right of the marble q, as shown 1/27/2018 Type here to searchExplanation / Answer
(A) Fe = q E
Fe = (1.6 x 10^-19) (1.33 x 10^5)
Fe = 2.128 x 10^-14 N
a = Fe / m = 2.128 x 10^-14 / (1.67 x 10^-27)
a = 1.274 x 10^13 m/s^2
vf^2 - vi^2 = 2 a d
v^2 - 0^2 = 2(1.274 x 10^13) (0.02)
v = 7.14 x 10^5 m/s ........Ans
(B) v^2 - 0^2 = 2(1.274 x 10^13)(0.20)
v = 2.26 x 10^5 m/s .....Ans
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