Two forces, of magnitudes F 1 = 80.0 N and F 2 = 45.0 N , act in opposite direct

Question

Two forces, of magnitudes F1 = 80.0 N and F2 = 45.0 N , act in opposite directions on a block, which sits atop a frictionless surface, as shown in the figure. (Figure 1) Initially, the center of the block is at position xi = -1.00 cm . At some later time, the block has moved to the right, and its center is at a new position, xf = 3.00 cm

Part A

Find the work W1 done on the block by the force of magnitude F1 = 80.0 N as the block moves from xi = -1.00 cm to xf = 3.00 cm .

Express your answer numerically, in joules.

Part B

Find the work W2 done by the force of magnitude F2 = 45.0 N as the block moves from xi = -1.00 cm to xf = 3.00 cm .

Express your answer numerically, in joules.

Part C

What is the net work Wnet done on the block by the two forces?

Express your answer numerically, in joules.

Part D

Determine the changeKfKi in the kinetic energy of the block as it moves from xi = -1.00 cm to xf = 3.00 cm .

Express your answer numerically, in joules.

Explanation / Answer

A)W1=F1*dx = 80.0*[3.00-(-1.00)]= 240 J

A)W2=F2*dx = 45.0*[3.00-(-1.00)]= 180 J

C)Wnet = W1+W2 = 240+180 = 420 J

D)KE = Wnet = 420 J

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