Two forces equal in magnitude and opposite in direction, acting on an object at

Question

Two forces equal in magnitude and opposite in direction, acting on an object at two different points, form what is called a couple. Two antiparallel forces with equal magnitudes F1=F2=7.70 N are applied to a rod as shown in the figure (Figure 1) .

A-

What should the distance l between the forces be if they are to provide a net torque of 6.20 N?m about the left end of the rod?

B-Is the sense of this torque clockwise or counterclockwise?

C-Repeat part A for a pivot at the point on the rod where F? 2 is applied.

D-

Repeat part B for a pivot at the point on the rod where F? 2 is applied.

Repeat part B for a pivot at the point on the rod where  is applied.

Explanation / Answer

torque due to F1 = T1 = F1*3 = 7.7*3 = +23.1 Nm

torque due to F2 = T2 = 7.7*(3+l) = = -23.1- 7.7l Nm

net torque = T1 + T2 = -7.7l

given net torque = 6.2 Nm

7.7*l = 6.2

l = 0.81 m

B)

clockwise

c)

net torque = F1*l = 7.7*0.805 = 6.2Nm

D)

clockwise

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