Two forces are applied to a car in an effort to move it, where F1 = 403 N and F2

Question

Two forces are applied to a car in an effort to move it, where F1 = 403 N and F2 = 388 N. (Assume up and to the right as positive directions.) F1= 10 degrees and F2= 30 degrees. A) What is the resultant of these two forces? Magnitude= ? (N) Direction= ? (Degrees) B) If the car has a mass of 3,000 kg, what acceleration does it have? Ignore friction. (m/s^2) Two forces are applied to a car in an effort to move it, where F1 = 403 N and F2 = 388 N. (Assume up and to the right as positive directions.) F1= 10 degrees and F2= 30 degrees. A) What is the resultant of these two forces? Magnitude= ? (N) Direction= ? (Degrees) B) If the car has a mass of 3,000 kg, what acceleration does it have? Ignore friction. (m/s^2) A) What is the resultant of these two forces? Magnitude= ? (N) Direction= ? (Degrees) B) If the car has a mass of 3,000 kg, what acceleration does it have? Ignore friction. (m/s^2)

Explanation / Answer

A. To add these two resultant forces you will need to find the forces in the x and y direction for both forces and then add the x forces together and the y forces together and plug them into this equation... R2=x2+y2 To find the forces in the x and y direction use your trig. So, F1sin(10) will give you the force in the y direction and F1cos(10) will give you the force in the x direction. Then do the same thing to find the force in the x and y direction for the F2 force. Then add the two forces in the x direction and add the two forces in the y direction. Then use those two numbers and solve for R in the equation given above. To find direction you will use tan-1(y/x). That will give you the angle.

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