Two first-order rate constants, K r andK p and one second-order rate constant, K

Question

Two first-order rate constants, Kr andKp and one second-order rate constant, Kfdefine KM by the relationship    Km = (Kr+ Kp)/Kf by substituting the appropriate units for the rate constantsin this expression, show that Km must be expressed in terms ofconcentration. Two first-order rate constants, Kr andKp and one second-order rate constant, Kfdefine KM by the relationship    Km = (Kr+ Kp)/Kf by substituting the appropriate units for the rate constantsin this expression, show that Km must be expressed in terms ofconcentration.

Explanation / Answer

and the units for rate constants in second order reactions is 1/(M*s)
Where s is seconds and M is concentration in molarity or mol/liter
now let's substitute for Km=(Kr +Kp)/Kf Km=[(1/s) + (1/s)] / [(1/M*s)] Km=[(2/s)] / [(1/M*s)] Km= [(2/s)] * [(M*s)] Km=(2*M*s)/s Km= 2M And 2M is units of concentration thus proving yourquestion Hope this helps!
Where s is seconds and M is concentration in molarity or mol/liter
now let's substitute for Km=(Kr +Kp)/Kf Km=[(1/s) + (1/s)] / [(1/M*s)] Km=[(2/s)] / [(1/M*s)] Km= [(2/s)] * [(M*s)] Km=(2*M*s)/s Km= 2M And 2M is units of concentration thus proving yourquestion Hope this helps!

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