A wire runs horizontally with a current of 1.0 A travelling to the left. This wi

Question

A wire runs horizontally with a current of 1.0 A travelling to the left. This wire experiences a uniform magnetic field of 32 m directed vertically upwards. What is the magnetic force per length on the wire? 32.0 N/m into the page 0.032 N/m into the page 0.032 N/m out of the page 32.0 N/m out the page A one turn motional EMF is changed from left to right in 0.2 seconds by moving a 1.00 meter long rod through a 0.75 T field at 10 m/s. Find the induced EMF created. 7.50 V 22.5 V 0.75 V 11.3 V A bar magnet is held above a single loop of wire with its North Pole directed downwards; for simplicity we can say that initially the loop is far enough away so that it is not encountering the magnetic field of the bar magnet. When the magnet is dropped, choose the best explanation to describe the direction of the induced current through the loop as the magnet approaches the wire? Due to a loss of magnetic flux, the induced current flows clockwise Due to a loss of magnetic flux, the induced current flows counter-clockwise Due to a gain in magnetic flux, the induced current flows counter-clockwise Due to a gain in magnetic flux, the induced current flows clockwise

Explanation / Answer

here,

the current in the wire , I = 1 A

uniform magnetic feild , B = 32 mT

B = 0.032 T

the magnetic force per unit length , F = I *( l X B) /l

F = 1 * 0.032 N/m

F = 0.032 N/m

as current is towards left and magnetic feild is upwards

using right hand rule

the direction of force is out of the page

the magnetic force per unit length c) 0.032 N/m out of the page

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