A flat sheet of paper of area 0.355 m2 is oriented so that the normal to the she

Question

A flat sheet of paper of area 0.355 m2 is oriented so that the normal to the sheet is at an angle of 58 to a uniform electric field of magnitude 20 N/C .

Part A

Find the magnitude of the electric flux through the sheet.

Express your answer using two significant figures.

SubmitMy AnswersGive Up

Part B

Does the answer to part A depend on the shape of the sheet?

SubmitMy AnswersGive Up

Part C

For what angle between the normal to the sheet and the electric field is the magnitude of the flux through the sheet largest?

Express your answer using two significant figures.

SubmitMy AnswersGive Up

Part D

For what angle between the normal to the sheet and the electric field is the magnitude of the flux through the sheet smallest?

Express your answer using two significant figures.

A flat sheet of paper of area 0.355 m2 is oriented so that the normal to the sheet is at an angle of 58 to a uniform electric field of magnitude 20 N/C .

Part A

Find the magnitude of the electric flux through the sheet.

Express your answer using two significant figures.

=   Nm2/C  

SubmitMy AnswersGive Up

Part B

Does the answer to part A depend on the shape of the sheet?

Does the answer to part A depend on the shape of the sheet? yes no

SubmitMy AnswersGive Up

Part C

For what angle between the normal to the sheet and the electric field is the magnitude of the flux through the sheet largest?

Express your answer using two significant figures.

=     

SubmitMy AnswersGive Up

Part D

For what angle between the normal to the sheet and the electric field is the magnitude of the flux through the sheet smallest?

Express your answer using two significant figures.

=

Explanation / Answer

The flux of a uniform electric field "E" crossing a plane surface "A" at angle "theta" is;

Flux = EACos(theta)

a) Flux = (20)(.355)Cos(58) = 3.76 N-m^2/C

b) No. For a plane surface the flux only depends on the area, not the shape.

c) Cos(theta) is a maximum (= 1) at theta = 0 deg (E crossing perpendicularly) and is a minumim (=0) at theta = 90 deg (E skimming over the surface)
So theta = 0 gives max flux and theta = 90 gives minimum (zero) flux

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.