PLEASE ANSWER BOTH QUESTIONS!!!!!! 1. A uniform electric field of magnitude 425

Question

PLEASE ANSWER BOTH QUESTIONS!!!!!!

1. A uniform electric field of magnitude 425 N/C pointing in the positive x-direction acts on an electron, which is initially at rest. The electron has moved 3.00 cm.

(a) What is the work done by the field on the electron?
J

(b) What is the change in potential energy associated with the electron?
J

(c) What is the velocity of the electron?

magnitude m/s direction ---Select--- +x -x +y -y




2.
A proton is released from rest in a uniform electric field of magnitude 418 N/C.(a) Find the electric force on the proton. magnitude     N direction     ---Select--- in the direction of the electric field in the opposite direction of the electric field The magnitude is zero.
(b) Find the acceleration of the proton. magnitude     m/s2 direction     ---Select--- in the direction of the electric field in the opposite direction of the electric field The magnitude is zero.
(c) Find the distance it travels in 1.98 s.
cm

Explanation / Answer

1.

a)

work done by the field on the electron

W=qEd=(1.6*10-19)*425*0.03

W=2.04*10-18 J

b)

change in potential energy

dU=-W=-2.04*10-18 J

c)

By conservation of energy

(1/2)mV2=2.04*10-18

(1/2)*(9.11*10-31)*V2=2.04*10-18

V=2.12*106 m/s

in negative x direction

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