A solid conductor sphere of radius a has a positive net charge 2Q. A conductor s

Question

A solid conductor sphere of radius a has a positive net charge 2Q. A conductor spherical shell of inner radius b and external radius c has the same center with the solid sphere and has a net charge Q. Using Gauss' Law determine the electric field in the regions denoted as (1), (2), (3) y (4) in the figure below, and the charge distribution over the shell when all the system is in electrostatic equilibrium. Note that this is a standard problem that is discussed in many textbooks. Solve this one without looking at the solution. That will help you be sure

Explanation / Answer

(A) field inside conductor is always zero.

for region 1:

E = 0

(B) for region 2:

Qin = 2Q

Applying Gauss Law,

E ( 4 pi r^2) = 2 Q / e0

E = Q / (2 pi e0 r^2 )

(c) For region 3:

E = 0 { inside conductor}

(D) For region 4:

Qin = 2Q - Q = Q

E ( 4 pi r^2 ) = Q / e0

E = Q / (4 pi e0 r^2 )

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