205B Homework No. M Mathway I Math Probl SalukiNet Homepage PHYS-255B Search Tex
ID: 1524089 • Letter: 2
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205B Homework No. M Mathway I Math Probl SalukiNet Homepage PHYS-255B Search Textbook Solu C www.webassign.net/web/Student/Assignment-Responses/last?dep 15617266 6. 214 points I Previous Answers SerpSE9 23 P.031. My Notes Ask Your Teache Three point charges are located on a circular arc as shown in the figure below. (Take r 4.24 cm. Let to the right be the +x direction and up along the screen be the +y direction +3.00 nC 2.00 nC 30.0 80.0 3.00 nC (a) What is the total electric field at P, the center of the arc? E 3355e4 Your response differs from the correct an by more than 100%. i 0 swer (b) Find the electric force that would be exerted on a -4.58-nC point charge placed at P. F 2e4. Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.i 0 Need Help? Read It 7. 11 points I Previous Answers SerPSE9 23 P.033 My Notes Ask Your Teacher A small, 2.00-g plastic ball is suspended by a 21.1-cm ong string in a uniform electric field as shown in the figure below. If the ball is in equilibrium when the string makes a 16.6 angleExplanation / Answer
a)
the electric field in y direction due to 3nC charge will cancell each other
Ex due to 3 nC = K*q*cos 30/r^2
= (9*10^9)*(3*10^-9)*cos 30 / (4.24*10^-2)^2
= 1.3007*10^4 N/C
This will be directed along positive x axis
Ex due to -2nC = K*q/r^2
= (9*10^9)*(2*10^-9)/ (4.24*10^-2)^2
= 1.0012*10^4 N/C
This will be directed along negative x axis
net field in x direction = 2*1.3007*10^4 N/C - 1.0012*10^4 N/C = 1.6002*10^4 N/C
Answer: (1.6002*10^4 i + 0 j) N/C
b)
F = q*Enet
= (-4.5*10^-9)*1.6002*10^4 i + 0 j
= -7.2009*10^-5 i + 0 j
Answer: (-7.2009*10^-5 i + 0 j) N
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