2018-2019 AP Physics 1 (Ch 03 HW Problem 3.71 Constans Part A A baskerballis sho

Question

2018-2019 AP Physics 1 (Ch 03 HW Problem 3.71 Constans Part A A baskerballis shot from an initial height of 2 40m Fiqure 1) with an inital speed no 10 ms directed at an angle 6 37 above the horiontal How far from the basket was the player i he made a basket? Express your answer to two significant figures and include the appropriate units Figure Valne Units Submit Request Arswer 10 ft 3.05 m 240 Part B At what angle to the horizontal ded the ball enber the basket? Express your answer to two significant figures and include the appropriate units. O Type here to search

Explanation / Answer

A)

Range, R = u^2 sin2(theta)/g

R = 10^2 x sin74/9.8 =9.81 m

B)

Maximum height h = (10 x sin37)^2/(2 x 9.8) = 1.85 m

So total height is 1.85 + 2.4 = 4.25 m

V^2 = u^2 + 2gh

V^2 = 0 + 2 x 9.8 x (4.25 - 3.05)

V = 4.85 m/s

In x direction, speed remains unchanged

= 10 x cos37 = 7.99 m/s

Theta = arctan (4.85/7.99) = 31.27 degree

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