A uniform disk with mass m = 9.24 kg and radius R = 1.41 m lies in the x-y plane

Question

A uniform disk with mass m = 9.24 kg and radius R = 1.41 m lies in the x-y plane and centered at the origin. Three forces act in the +y-direction on the disk: 1) a force 339 N at the edge of the disk on the +x-axis, 2) a force 339 N at the edge of the disk on the –y-axis, and 3) a force 339 N acts at the edge of the disk at an angle = 38° above the –x-axis.

1) What is the magnitude of the torque on the disk about the z axis due to F1?

2) What is the magnitude of the torque on the disk about the z axis due to F2?

3) What is the magnitude of the torque on the disk about the z axis due to F3?

4) What is the x-component of the net torque about the z axis on the disk?

Explanation / Answer

1)     What is the magnitude of the torque on the disk about the z axis due to F1?

= (R)(F1)

=1.41x339N

=477.99 N-m

2)What is the magnitude of the torque on the disk about the z axis due to F2?

Ans) = (R)(F2)(sin180°)

      =1.41x339x0

=0

3)What is the magnitude of the torque on the disk about the z axis due to F3?

Ans) =(R)(F3)(sin(270° + 38°)

=1.41x339x-0.788    (-Z direction)

=376.6N-m

4)What is the x-component of the net torque about the z axis on the disk?

Ans) the x-component of the net torque about the z axis on the disk is zero(0)

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