A uniform disk with mass m = 9.26 kg and radius R = 1.42 m lies in the x-y plane

Question

A uniform disk with mass m = 9.26 kg and radius R = 1.42 m lies in the x-y plane and centered at the origin. Three forces act in the +y-direction on the disk: 1) a force 342 N at the edge of the disk on the +x-axis, 2) a force 342 N at the edge of the disk on the –y-axis, and 3) a force 342 N acts at the edge of the disk at an angle = 38° above the –x-axis.

1) What is the magnitude of the torque on the disk about the z axis due to F1?

2) What is the magnitude of the torque on the disk about the z axis due to F2?

3) What is the magnitude of the torque on the disk about the z axis due to F3?

4) What is the x-component of the net torque about the z axis on the disk?

5) What is the y-component of the net torque about the z axis on the disk?

6) What is the z-component of the net torque about the z axis on the disk?

7) What is the magnitude of the angular acceleration about the z axis of the disk?

8) If the disk starts from rest, what is the rotational energy of the disk after the forces have been applied for t = 1.8 s?

PLEASE SHOW STEPS

Explanation / Answer

torque = force * distance * sin(theta)

magnitude of the torque on the disk about the z axis due to F1 = F1 * radius * sin(90)

magnitude of the torque on the disk about the z axis due to F1 = 342 * 1.42 * sin(90)

magnitude of the torque on the disk about the z axis due to F1 = 485.64 Nm

magnitude of the torque on the disk about the z axis due to F2 = F2 * radius * sin(0)

magnitude of the torque on the disk about the z axis due to F2 = 0 Nm

magnitude of the torque on the disk about the z axis due to F3 = F3 * radius * sin(90 - 38)

magnitude of the torque on the disk about the z axis due to F3 = 342 * 1.42 * sin(90 - 38)

magnitude of the torque on the disk about the z axis due to F3 = 382.689 Nm

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.