Unpolarized light of intensity 20 W / c m 2 is incident on a linear polarizer se

Question

Unpolarized light of intensity 20 W/cm2 is incident on a linear polarizer set at the polarizing angle 1 = 23 . The emerging light then passes through a second polarizer that is set at the polarizing angle 2= 154 . Note that both polarizing angles are measured from the vertical.
What is the intensity I2 of the light after passing through both polarizers? Express your answer in watts per square centimeter using three significant figures. Unpolarized light of intensity 20 W/cm2 is incident on a linear polarizer set at the polarizing angle 1 = 23 . The emerging light then passes through a second polarizer that is set at the polarizing angle 2= 154 . Note that both polarizing angles are measured from the vertical.
What is the intensity I2 of the light after passing through both polarizers? Express your answer in watts per square centimeter using three significant figures.
What is the intensity I2 of the light after passing through both polarizers? Express your answer in watts per square centimeter using three significant figures. What is the intensity I2 of the light after passing through both polarizers? Express your answer in watts per square centimeter using three significant figures. What is the intensity I2 of the light after passing through both polarizers? Express your answer in watts per square centimeter using three significant figures.

Explanation / Answer

let,

original intensity is Io=20 W/cm^2

theta1=23 degerees,

theta2=154 degrees,

use,

after first polarizer,

I1=Io/2*cos^(23) ---( for linear polarizer)

I1=20/2*cos^2(23)

I1=8.473 W/cm^2

now,

after second polarizer,

I2=I1*cos^(154-23)

I2=8.473*cos^2(154-23)

I2=3.65 W/cm^2 ------->

Related Questions

Navigate

• Browse (All)
• Browse U
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.