A uniform 600 kg beam, 6 m long, is freely pivoted at P. The beam is supported i

Question

A uniform 600 kg beam, 6 m long, is freely pivoted at P. The beam is supported in a horizontal position by a light strut, 5 m long, which is freely pivoted at Q and is loosely pinned to the beam at R. A load of mass is suspended from the end of the beam at S. A maximum compression of 18, 000 N in the strut is permitted, due to safety. In the figure, under maximum load, the x-component of the force exerted on the beam by the pivot at P is closest to: A) 14, 400 N B) 16, 200 N C) 10, 800 N D) 18, 000 N E) 12, 600 N

Explanation / Answer

The compression in strut means, force at R for the beam.
The x component of this force would be balanced by the x-component of the force exerted on the beam by pivot P [ as ther eis no other x - direction force]
So Fx = 18000sin(theta) = 18000*3/5 = 10800 N

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