University of Connecticut X CIf You Have 0.251 M3 of b.hr Julianne Houg C fi WWW

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University of Connecticut X CIf You Have 0.251 M3 of b.hr Julianne Houg C fi WWW. Saplinglea rning com /ibiscms/mod/ibis/view.php?id-2099836 E: Apps O O UCHC candidate Sel... S One Card office D This week's Menus O Best Medical School... Bb My Courses Black... M- University of Conne... P MyLab & Mastering Attempts Score Print Calculator Periodic Table Available From 8/2015 06:00 PM Questi of 15 12/10/2015 11:00 PM Due Date Map Points Possible 100 Grade Category: Graded A uniform steel plate has an area of 0.961 m2. When subjected to a temperature difference between its sides, a heat current of 34100 W is found to flow through it. What is the temperature gradient? Description: What is the temperature difference when the plate is 0.0433 m thick? The thermal conductivity of steel is 50.2 W/(m. K) Policies: Homework Temperature gradient heck y Number plete up on any question You can keep trying to answer each question until Temperature difference: you get it right or give up You lose 5% of the points available to each answer ct att O eTextbook The heat current is the amount of heat that flows per unit time OHelp With This Topic Web Help & Videos O Technical Support and Bug Reports Previous Give Up & View Solution 2 Check Answer Next Exit pyright 20 2015 Sapling Le tact 4:53 PM 2/10/2015

Explanation / Answer

heat current dQ/dt = K*A*dT/L

temparature gradient dT/L = (dQ/dt)/(K*A)

dQ/dt = 34100 W

K = 50.2 W/m-K

A = 0.961 m^2

dT/L = (34100)/(50.2*0.961) = 706.85 K/m

temparature difference is dT = 706.85*L = 706.85*0.0433 = 30.6 K

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