A 500kg, 4-m diameter merry-go-round is rotating at 6pi rad\'s (assume a uniform

Question

A 500kg, 4-m diameter merry-go-round is rotating at 6pi rad's (assume a uniform disk). 60kg hard-partying college student drops straight down form a low tree branch onto the very edge of the merry-go-round and holds on. What is the moment of inertia of the merry-go-round rotating about its center? What is the moment of inertia of a student rotating about the center of the merry-go-round? (Treat them as a point mass.) What is the final angular velocity of the system after the collision? A 500-g aluminum cup holds 300 g of water. The water and aluminum are 40 degreeC. A 200-g block of iron at 0 degreeC is placed in the water. Find the final the system.

Explanation / Answer

a) You have rightly calculate this part (I for disc = mr2/2)

b) You have correctly calculated this part too (I for particle = mr2)

c) You have correctly used the conservation of angluar momentum to calculate the final angular velocity as 15.2 rad/s.

If you want to express it in revolutions, you need to do as revolutions per second rather than just revolution. Also the value expressed to 2 decimal place would be 2.42 revolutions / second.

(Note that it is standard to express angular velocity as radians/second as this is the SI unit)

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