A 500 g block is released from rest at a height y0 above a vertical spring with
ID: 1579058 • Letter: A
Question
A 500 g block is released from rest at a height y0 above a vertical spring with spring constant k = 400 N/m and negligible mass. The block sticks to the spring and momentarily stops after compressing the spring 18.0 cm. How much work is done (a) by the block on the spring, (b) by the spring on the block? (c) What is the value of y0? (d) If the block were released from the height 1.5y0 above the spring, what would be the maximum compression of the spring?
Just answer B please.
A. A pendulum, consisting of a ball of mass m 0.5 kg attached to the end of a massless cord of length 0.75 m, can swing vertically about the upper end which is fixed. The ball is pulled aside to an angle of = 30° from the vertical and released from rest. (a) What is the speed of the ball at the lowest point? (b) Does this speed increase, decrease, or remain the same if the angle is increased? B. A 500 g block is released from rest at a height yo above a vertical spring with spring constant k = 400 N/m and negligible mass. The block sticks to the spring and mom entarily stops after compressing the spring 18.0 cm. How much work is done (a) by the block on the spring, (b) by the spring on the block? (c) What is the value of yo? (d) If the block were released from the height 1.5yo above the spring, what would be the maximum compression of the spring?Explanation / Answer
a] work done by the block on the string = 0.5 kx^2 = 0.5*400*0.18^2 = 6.48 J answer
b] work done by string on the block = - 0.5 kx^2 = - 6.48 J answer
c] since work done by gravity and spring must add to zero,
mgh = 6.48
h = 6.48/[0.500*9.8] = 1.32 m
y0 = 1.32 - 0.18
= 1.14 m answer
d] since work done by gravity and spring must add to zero,
mgh = 0.5kx^2
0.5*9.8*[1.14*1.5+x] = 0.5*400*x^2
x = 0.217 m = 21.7 cm answer
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