A 15000-N crane pivots around a friction-free axle at its base and is supported

Question

A 15000-N crane pivots around a friction-free axle at its base and is supported by a cable making a 25 ? angle with the crane (the figure (Figure 1) ). The crane is 16 m long and is not uniform, its center of gravity being 7.0 m from the axle as measured along the crane. The cable is attached 3.0 m from the upper end of the crane.

Part A

When the crane is raised to 55 ? above the horizontal holding an 11000-N pallet of bricks by a 2.2-m very light cord, find the tension in the cable.

Express your answer using two significant figures.

Part B

Find the horizontal component of the force that the axle exerts on the crane.

Express your answer using two significant figures.

Part C

Find the vertical component of the force that the axle exerts on the crane.

Express your answer using two significant figures.

Explanation / Answer

In equilibrium net torque = 0

W1 = 15000 N

W2 = m*g = 11000 N

l1 = 7m

l2 = 16

the rope is tied at l = 13 m

W1*l1*cos55 + w2*l2*cos55 = T*sin25*l

(15000*7*cos55) + (11000*16*cos55) = T*sin25*13

T = 29336.34 N

-------

partB

along horzantal

Fh - T*cos30 = 0

Fh = 25406.02 N

part(c)

along vertical

Fv - T*sin30 - W1 - w2 = 0

Fv = 29336.34*sin30 + 15000 + 11000

Fv = 40668.2 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.