You are performing an analysis of a new metalic alloy created in your research l

Question

You are performing an analysis of a new metalic alloy created in your research lab. You place a 20.5 kg block of this new metal initially at a temperature 15 oC in a rigid insulated box. 0.15 kg of steam at 100 oC is piped into the box and then the box is sealed so that no heat can be transfered in or out. When the system comes to equilibrium, the temperature is 68 oC.

What is the specific heat of the metal? Give your answer in J/kg * degC (or equivalently J/kg * K), and give your answer to at least 3 significant digits.

Do not include units in your answer.

Explanation / Answer

heat lost by steam = heat gained by block

Msteam*( Lv + Cw*dT1 ) = Mblock*Cblock*dT2

0.15*(2260*10^3 + (4190*(100-68))) = 20.5*c*(68-15)

c = 330.5

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