A photon with an initial wavelength of 1.190 Times 10^-11 m Compton scatters fro

Question

A photon with an initial wavelength of 1.190 Times 10^-11 m Compton scatters from an electron which is initially at rest. The photon scatters at an angle of 180 degree (straight back), and the wavelength of the scattered photon is 1.676 Times 10^-11 m. What is the magnitude of the momentum of the incoming photon? What is the magnitude of the momentum of the outgoing photon? What is the magnitude of the momentum of the electron after the collision? What is the energy of the incoming photon? What is the energy of the outgoing photon? What is the kinetic energy of the scattered electron?

Explanation / Answer

A) P1 = h/lamda1

= 6.625*10^-34/(1.19*10^-11)

= 5.567*10^-23 kg.m/s

B) P2 = h/lamda2

= 6.625*10^-34/(1.676*10^-11)

= 3.953*10^-23 kg.m/s

C) Apply conservation of momentum

P1 = P2 + Pe

==> Pe = P1 - P2

= (5.567 - (-3.953))*10^-23

= 9.52*10^-23 kg.m/s

D) E1 = h*c/lamda1

= 6.625*10^-34*3*10^8/(1.19*10^-11)

= 1.67*10^-14 J

E) E2 = h*c/lamda2

= 6.625*10^-34*3*10^8/(1.676*10^-11)

= 1.186*10^-14 J

F) Kinetic energy of Photon = E1 - E2

= (1.67 - 1.186)*10^-14

= 4.84 *10^-15 J

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