A spaceship of mass 2.1×10 6 kg is cruising at a speed of 4.4×10 6 m/s when the

Question

A spaceship of mass 2.1×106 kg is cruising at a speed of 4.4×106 m/s when the antimatter reactor fails, blowing the ship into three pieces. One section, having a mass of 4.8×105 kg , is blown straight backward with a speed of 2.4×106 m/s . A second piece, with mass 8.1×105 kg , continues forward at 1.3×106 m/s .

Part A

What is the speed of the third piece?

Express your answer using two significant figures.

Part B

What is the directionof the third piece?

What is the directionof the third piece?

or Straight forward

Explanation / Answer

Net momentum in the beginning = mv = 2.1*10^6*4.4*10^6 = 9.24*10^12 kg m /s

Momentum of the other two pieces = (4.8*10^5)*(-2.4*10^6) + (8.1*10^5)*(1.3*10^6)

                                     = -0.99*10^11 kg m /s

so , Momentum of the third piece

        = 9.24*10^12 + 0.99 * 10^11

        = 9.339*10^12 kg m /s

mass of the third piece = 2.1*10^6 - ( 4.8*10^5 + 8.1*10^5)

mass of the third piece = 8.1*10^5 kg

so the speed of the third piece = momentum / mass

V = 9.339*10^12 / 8.1*10^5

V = 1.15*10^7 m/s

a)velvoity of the third part is 1.15*10^7 m/s

b) since the mometum is +ve so the direction of the third piece is straight forward

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