A 8430-kg car is travelling at 29.7 m/s when the driver decides to exit the free

Question

A 8430-kg car is travelling at 29.7 m/s when the driver decides to exit the freeway by going up a ramp. After coasting 383 m along the exit ramp the car's speed is 12.7 m/s, and it is h = 13.7 m above the freeway. What is the magnitude of the average drag force exerted on the car?

A 8430-kg car is travelling at 29.7 m/s when the driver decides to exit the freeway by going up a ramp. After coasting 383 m along the exit ramp the car's speed is 12.7 m/s, and it is h = 13.7 m above the freeway. What is the magnitude of the average drag force exerted on the car? Number drag

Explanation / Answer

Given - Mass of the car = 8430 kg

    initial speed of the car = 29.7   , final speed of the car = 12.7 m/s

Energy difference = Energy in the beginning - Energy at the end

E = 0.5mv1^2 - (0.5mv2^2 + mgh)

E = 8430 ( 0.5*29.7^2 - (0.5*12.7^2+9.8*13.7))

E = 1906360 J

Work is done against this energy to overcome the drag

Work done = force* displacement

W =Fd * S

1906360 = Fd * 383

Fd = 4977.44 N

so the average drag force is 4977.44 N

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