A 808 kg automobile is moving at 15.0 m/s at a height of 5.0 m above the bottom

Question

A 808 kg automobile is moving at 15.0 m/s at a height of 5.0 m above the bottom of a hill when it runs out of gasoline. The car coasts down the hill and then continues coasting up the other side until it comes to rest. Ignoring frictional forces and air resistance, what is the value ofh, the highest position the car reaches above the bottom of the hill?
m

A 808 kg automobile is moving at 15.0 m/s at a height of 5.0 m above the bottom of a hill when it runs out of gasoline. The car coasts down the hill and then continues coasting up the other side until it comes to rest. Ignoring frictional forces and air resistance, what is the value ofh, the highest position the car reaches above the bottom of the hill?

Explanation / Answer

Initial Energy = PE + KE = 0.5*808*15^2 + 808*9.8*5 = 130492 J

Final = mgh

808*9.8*h = 130492

h = 130492/(808*9.8)

h = 16.479 m

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